Series Pattern Program for (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n) in Python, C, C++ and Java
This article discusses, how to write a prorgram to solve Series Pattern Program for (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n) series in python, C, C++ and Java.
Problem Definition
Write a prorgram to solve Series Pattern Program for (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n) series in python, C, C++ and Java.
Sample input and Output:
Enter the value of n: 5 Sum is: 55
Source code to solve the series pattern (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n) in python
sum = 0 n = int (input("Enter the value of n:")) for i in range(1,n+1): sum = sum + (i * i) print ("Sum is: ", sum)
Source code to solve the series pattern (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n) in C
#include <stdio.h>int main() { int i,n,sum=0; printf ("Enter the value of n:"); scanf ("%d", &n); for(i=1;i<=n;i++) { sum += i * i; } printf("Sum is: %d",sum); return 0; }
Source code to solve the series pattern (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n) in CPP (C++)
#include <iostream>using namespace std; int main() { int i,n,sum=0; cout << "Enter the value of n:"; cin >> n; for(i=1;i<=n;i++) { sum += i * i; } cout << "Sum is: " << sum; return 0; }
Source code to solve the series pattern (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n) in Java
import java.util.Scanner; class Series2 { private static Scanner scan; public static void main(String[] args) { int i, n, sum = 0; scan = new Scanner(System.in); System.out.println("Enter the value of n:"); n = scan.nextInt(); for(i=1;i<=n;i++) { sum += i * i; } System.out.print("Sum is: " + sum); } }
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This article discusses, how to write a program to display Series Pattern (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n) in Python, C, CPP (C++), and Java programming language with the video tutorials.
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