Series Pattern Program for 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n
This article discusses, how to write a prorgram to solve 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n series in python, C, C++ and Java.
Problem Definition
Write a prorgram to solve 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n series in python, C, C++ and Java.
Sample input and Output:
Enter the value of n: 5 Sum is: 34
Source code to solve the series 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n in python
sum = 0
n = int (input("Enter the value of n:"))
for i in range(1,n+1):
fact = 1
for j in range(1, i+1):
fact = fact * j
sum = sum + (fact/i)
print ("Sum is: ", sum)Source code to solve the series 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n in C
#include <stdio.h>
int main()
{
int i, j, n, sum = 0, fact;
printf("Enter the value of n:");
scanf("%d", &n);
for(i=1; i<=n; i++)
{
fact = 1;
for (j = 1; j <= i; j++)
{
fact = fact * j;
}
sum = sum + (fact / i);
}
printf("Sum is: %d", sum);
return 0;
}Source code to solve the series 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n in CPP (C++)
#include <iostream>
using namespace std;
int main()
{
int i, j, n, sum = 0, fact;
cout <<"Enter the value of n:";
cin >> n;
for(i=1; i<=n; i++)
{
fact = 1;
for (j = 1; j <= i; j++)
{
fact = fact * j;
}
sum = sum + (fact / i);
}
cout << "Sum is: "<< sum;
return 0;
}Source code to solve the series 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n in Java
import java.util.Scanner;
class Series4
{
private static Scanner scan;
public static void main(String[] args)
{
int i, j, n, sum = 0, fact;
scan = new Scanner(System.in);
System.out.println("Enter the value of n:");
n = scan.nextInt();
for(i=1;i<=n;i++)
{
fact = 1;
for (j = 1; j <= i; j++)
{
fact = fact * j;
}
sum = sum + (fact / i);
}
System.out.print("Sum: " + sum);
}
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This article discusses, how to write a program to display Series Pattern 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n in Python, C, CPP (C++), and Java programming language with the video tutorials.
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