Series Pattern Program for 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n
This article discusses, how to write a prorgram to solve 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n series in python, C, C++ and Java.
Problem Definition
Write a prorgram to solve 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n series in python, C, C++ and Java.
Sample input and Output:
Enter the value of n: 5 Sum is: 34
Source code to solve the series 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n in python
sum = 0 n = int (input("Enter the value of n:")) for i in range(1,n+1): fact = 1 for j in range(1, i+1): fact = fact * j sum = sum + (fact/i) print ("Sum is: ", sum)
Source code to solve the series 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n in C
#include <stdio.h> int main() { int i, j, n, sum = 0, fact; printf("Enter the value of n:"); scanf("%d", &n); for(i=1; i<=n; i++) { fact = 1; for (j = 1; j <= i; j++) { fact = fact * j; } sum = sum + (fact / i); } printf("Sum is: %d", sum); return 0; }
Source code to solve the series 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n in CPP (C++)
#include <iostream> using namespace std; int main() { int i, j, n, sum = 0, fact; cout <<"Enter the value of n:"; cin >> n; for(i=1; i<=n; i++) { fact = 1; for (j = 1; j <= i; j++) { fact = fact * j; } sum = sum + (fact / i); } cout << "Sum is: "<< sum; return 0; }
Source code to solve the series 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n in Java
import java.util.Scanner; class Series4 { private static Scanner scan; public static void main(String[] args) { int i, j, n, sum = 0, fact; scan = new Scanner(System.in); System.out.println("Enter the value of n:"); n = scan.nextInt(); for(i=1;i<=n;i++) { fact = 1; for (j = 1; j <= i; j++) { fact = fact * j; } sum = sum + (fact / i); } System.out.print("Sum: " + sum); } }
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This article discusses, how to write a program to display Series Pattern 1!/1 + 2!/2 + 3!/3 + 4!/4 + … + n!/n in Python, C, CPP (C++), and Java programming language with the video tutorials.
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